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Cribbage

4 bytes added, 08:36, March 24, 2007
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In Search of the Truth: Who's Better?
In the case of the 508 games played in the four years of cribbage competition, our expected number of wins for each player is 254. We can plug this value and the observed number of wins into the equation to determine the <math>\chi^2</math> value for the analysis:
:<math>\chi^2 = {(264 264_z - 254)^2 \over 254}+{(244 244_j - 254)^2 \over 254}</math>
:<math>\chi^2 \approx 0.787401575</math>
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